A uniform rod 9 m long weighing 40 kg is pivoted at a point 2 m from one end where a weight of 120 kg is suspended. The required force acting at the end in a direction perpendicular to rod to keep it equilibrium, at an inclination 60° with horizontal, is« Back to Previous Page

A. 40 kg B. 60 kg C. 10 kg D. 100 kg.
Posted by Civil Engineer
Asked on August 9, 2016 1:50 pm
0

C. 10 kg

Posted by Civil Engineer
Answered on August 9, 2016 1:51 pm